Answer: C. Draw the structure of \(\text{CH}_2\text{CHCH}_3\) (propene), \(\text{CH}_2=\text{CH-CH}_3\), and count every single line as one bond.
Going through the molecule: the C=C double bond between the first two carbons counts as 2 bonds. The C–C single bond between carbons 2 and 3 is 1 bond. Each C–H bond is 1 bond — and propene has 6 C–H bonds (2 on C₁, 1 on C₂, 3 on C₃).
Total covalent bonds = \(2 + 1 + 6 = 9\). Option C.
A (7) miscounts the C=C as 1; B (8) misses one of the C–H bonds; D (10) adds an extra bond.
Every O Level Pure Chemistry TYS MCQ solution video, plus full Sec 3 / Sec 4 topic recordings.
Find out more