Answer: B. Use conservation of atoms to identify product X.
Reactants: \(\text{PCl}_5\) and \(\text{C}_2\text{H}_5\text{OH}\) — combined atoms: 1 P, 5 Cl, 2 C, 6 H, 1 O.
Known products: \(\text{C}_2\text{H}_5\text{Cl}\) (2 C, 5 H, 1 Cl) + \(\text{HCl}\) (1 H, 1 Cl). Subtracting: remaining atoms in X = 1 P, 3 Cl, 0 C, 0 H, 1 O — i.e., \(\text{POCl}_3\).
\(M_r(\text{POCl}_3) = 31 + 16 + 3(35.5) = 153.5\). Mass of chlorine in X = \(3 \times 35.5 = 106.5\).
%Cl = \(\frac{106.5}{153.5} \times 100\% = 69.4\%\) → B.
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