
Answer: C. 2-methylpropane has the structure \((\text{CH}_3)_3\text{CH}\) — three equivalent methyl carbons and one tertiary CH carbon. There are 9 primary H atoms (on the three CH₃ groups) and 1 tertiary H atom.
Substituting two H atoms by Cl in \(\text{C}_4\text{H}_9\text{Cl}_2\) gives the following distinct isomers:
(i) both Cl on the same primary carbon: 1,1-dichloro-2-methylpropane.
(ii) one Cl each on two different primary carbons: 1,3-dichloro-2-methylpropane.
(iii) one Cl on a primary carbon, one Cl on the tertiary carbon: 1,2-dichloro-2-methylpropane.
(iv) one Cl on a primary carbon and another on the same tertiary carbon — but the tertiary C has only one H, so two Cl on it is impossible.
Counting: there are 4 distinct isomers.
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