Answer: D. Count chlorine atoms in each sample.
Sample X: 0.050 mol \(\text{Cl}_2\). Each \(\text{Cl}_2\) molecule has 2 chlorine atoms, so moles of Cl atoms = \(0.050 \times 2 = 0.100\) mol. Number of atoms = \(0.100 \times 6.02 \times 10^{23} = 6.02 \times 10^{22}\).
Sample Y: 0.10 mol \(\text{CCl}_4\). Each \(\text{CCl}_4\) molecule has 4 chlorine atoms, so moles of Cl atoms = \(0.10 \times 4 = 0.40\) mol. Number of atoms = \(0.40 \times 6.02 \times 10^{23} = 2.41 \times 10^{23}\).
Row D matches both values.
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