Answer: D. The reaction is \(\text{Na}_2\text{SO}_4(\text{aq}) + \text{Pb(NO}_3)_2(\text{aq}) \rightarrow \text{PbSO}_4(\text{s}) + 2\text{NaNO}_3(\text{aq})\).
Two salts are produced, not one. Lead(II) sulfate is insoluble (it appears as a white precipitate); sodium nitrate is soluble (all sodium salts and all nitrates are soluble).
Therefore one soluble salt and one insoluble salt are produced — option D. Options A and B claim only one salt forms, which contradicts the equation. Option C wrongly claims both products are soluble, ignoring \(\text{PbSO}_4\)'s insolubility.
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