
Answer: A. \(\text{SO}_2 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_3\) — sulfurous acid is acidic, so the solution has pH below 7; pH 3 fits (pH 9 would mean an alkaline solution, which is wrong). This rules out options C and D.
\(\text{SO}_2\) (or \(\text{H}_2\text{SO}_3\)) is a reducing agent. Acidified potassium manganate(VII) is a purple oxidising agent. When the reducing agent reacts with it, \(\text{MnO}_4^-\) (purple) is reduced to \(\text{Mn}^{2+}\) (colourless): the solution is therefore decolourised. 'No change' (options B and D) cannot happen with a reducing gas being bubbled through.
So pH 3 plus decolourisation — only row A combines both correctly.
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