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2022 O Level Chem P1 Q5 — Structure and Bonding Solution

Structure and Bonding 2022 O Level Pure Chemistry · Paper 1 · Q5

Question

Sand (silicon dioxide), diamond, graphite and iodine all contain covalent bonds. Which statement is correct?
  1. AGraphite is used as a lubricant because each layer in its structure is held to the next layer by strong covalent bonds.
  2. BDiamond has atoms that are arranged in a tetrahedral structure.
  3. CSilicon dioxide and graphite both have free electrons and therefore can conduct electricity.
  4. DUpon gentle warming, iodine changes from solid to gas as its covalent bonds are weak.
Correct answer: B

Video Solution

Explanation

Answer: B. Diamond is a giant covalent solid in which each carbon atom is covalently bonded to four others, arranged in a regular tetrahedral lattice. Statement B describes this correctly.

Option A is wrong: graphite is a lubricant because the layers are held to each other by weak intermolecular forces, not strong covalent bonds. The layers can slide.
Option C is wrong: graphite does conduct electricity (delocalised electrons between layers), but \(\text{SiO}_2\) does not — all valence electrons in \(\text{SiO}_2\) are locked into localised covalent bonds, so it is an insulator.
Option D is wrong: iodine changes from solid to gas on gentle warming because the intermolecular forces between \(\text{I}_2\) molecules are weak, not because the covalent bonds inside each \(\text{I}_2\) molecule are weak. The I–I bond itself is fairly strong; it's the dispersion forces between molecules that break.

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