Answer: B. Only the NaCl in the mixture reacts with \(\text{AgNO}_3\); the \(\text{NaNO}_3\) is inert here.
Moles of \(\text{AgNO}_3\) used \(= 0.02 \times \dfrac{29.4}{1000} = 5.88 \times 10^{-4}\) mol. Mole ratio \(\text{NaCl} : \text{AgNO}_3 = 1 : 1\), so moles of NaCl in the mixture \(= 5.88 \times 10^{-4}\) mol.
\(M_r(\text{NaCl}) = 23 + 35.5 = 58.5\). Mass of NaCl \(= 5.88 \times 10^{-4} \times 58.5 = 0.0344\) g.
Percentage by mass of NaCl in the mixture \(= \dfrac{0.0344}{0.060} \times 100 \approx 57.3\%\) — option B.
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