
Answer: B. Use the proton number to identify the element, and compare electrons with protons to decide atom or ion. P: 11 protons (sodium), 10 electrons → Na⁺. Q: 13 protons (aluminium), 13 electrons → a neutral Al atom. R: 17 protons (chlorine), 18 electrons → Cl⁻. S: 18 protons (argon), 18 electrons → a neutral Ar atom.
Option B is correct: P (Na⁺) and R (Cl⁻) are already a cation and an anion, and they combine to form the ionic compound sodium chloride, NaCl.
A is wrong (sodium and aluminium are metals); C is wrong (aluminium is reactive); D is wrong (chlorine is in Group VII while argon is in Group 0).
Every O Level Pure Chemistry TYS MCQ solution video, plus full Sec 3 / Sec 4 topic recordings.
Find out more