Answer: C (copper(II) sulfate). The method described — adding an excess of an insoluble solid to an acid, filtering off the unreacted solid, then crystallising the filtrate — is the standard route for making a soluble salt of a metal whose oxide or carbonate is insoluble in water. The excess solid guarantees all the acid is used up, and the leftover solid is simply filtered away.
Copper(II) sulfate fits perfectly: insoluble copper(II) oxide reacts with dilute sulfuric acid to give copper(II) sulfate solution, which is then crystallised. So C is correct.
Ammonium chloride (A) and potassium chloride (D) come from two soluble reactants, so they are made by titration, not by this excess-solid method. Barium sulfate (B) is insoluble in water, so it is made by precipitation, not by crystallising a filtrate. The answer is C.
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