
Answer: B (\(\Delta H\) is negative; energy to break bonds is less than energy released forming bonds). The combustion of hydrogen, \(2\text{H}_2(g) + \text{O}_2(g) \to 2\text{H}_2\text{O}(l)\), is strongly exothermic, so heat is given out and the enthalpy change \(\Delta H\) is negative.
Thinking in terms of bonds: breaking the H–H and O=O bonds in the reactants absorbs energy (endothermic), while forming the O–H bonds in water releases energy (exothermic). The overall \(\Delta H\) is the energy absorbed breaking bonds minus the energy released forming bonds.
Because the reaction releases heat overall, more energy must be given out forming the new bonds than is taken in breaking the old ones. So the energy needed to break bonds is less than the energy released making bonds, and \(\Delta H\) is negative. This is row B.
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