
Answer: A (X = C₂H₄, Y = C₄H₈). Cracking breaks the long alkane \(\text{C}_{10}\text{H}_{22}\) into smaller molecules: \(\text{C}_{10}\text{H}_{22} \to \text{C}_4\text{H}_{10} + \text{X} + \text{Y}\).
X has two carbon atoms and decolourises aqueous bromine, so X is an alkene with a C=C double bond — ethene, C₂H₄. The decolourising of bromine water is the standard test for unsaturation.
Now balance the equation. Carbon: \(10 = 4 + 2 + (\text{carbons in Y})\), so Y has 4 carbon atoms. Hydrogen: \(22 = 10 + 4 + (\text{hydrogens in Y})\), so Y has 8 hydrogen atoms. That makes Y = C₄H₈, butene, which is also an alkene formed during cracking.
So X = C₂H₄ and Y = C₄H₈, which is row A. The key checks are that an alkene is needed to decolourise bromine, and that the carbon and hydrogen atoms must balance on both sides.
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