Answer: B (vanadium has a high density). Vanadium is a transition metal, and transition metals are dense, hard metals with high melting points; a density of about 6 g/cm³ is typical, so B is correct.
Option A is wrong: a change from violet V²⁺ to blue-green V³⁺ means the oxidation state rises from +2 to +3, which is a loss of an electron, so that is oxidation, not reduction. Option C is wrong: vanadium compounds are good catalysts — vanadium(V) oxide, V₂O₅, is the catalyst in the Contact process for making sulfuric acid. Option D is wrong: vanadium has a very high melting point (around 1900 °C), as expected for a transition metal, not a low one.
The variable oxidation states and coloured ions in the question are themselves clues that vanadium is a transition element with typically high density, melting point and catalytic activity, so the answer is B.
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