WhatsApp Us
Home › TYS Solutions › O Level Chem › 2019 › P1 Q23

2019 O Level Chem P1 Q23 — Air and the Atmosphere / Composition of Air Solution

Air and the Atmosphere / Composition of Air 2019 O Level Pure Chemistry · Paper 1 · Q23

Question

The oxygen in air can be removed by passing over heated copper using the apparatus in the diagram. 50 cm³ of air is collected in gas syringe 1. Each syringe, 1 and 2, is pushed alternately so that the air passes repeatedly over the heated copper. When the volume of gas no longer changes, and the gas has cooled to room temperature, what volume of gas will remain?Question diagram
  1. A10 cm³
  2. B20 cm³
  3. C40 cm³
  4. D80 cm³
Correct answer: C

Video Solution

Explanation

Answer: C (40 cm³). Air is about 20% oxygen and 80% nitrogen, with only small traces of other gases. Passing the air repeatedly over heated copper removes the oxygen: \(2\text{Cu} + \text{O}_2 \to 2\text{CuO}\). The copper turns black as it forms solid copper(II) oxide, while nitrogen does not react.

Of the 50 cm³ of air, the oxygen is \(50 \times 0.20 = 10\,\text{cm}^3\). Once all the oxygen has been removed as solid copper oxide, the gas left is essentially nitrogen, with volume \(50 - 10 = 40\,\text{cm}^3\).

Measured after cooling back to room temperature, 40 cm³ remains, which is option C. This experiment is a classic way of showing that oxygen makes up roughly one fifth of air. The common error is to forget to cool the gas to room temperature or to misread the 20% oxygen figure.

Get the Sec 3 / Sec 4 recording package

Every O Level Pure Chemistry TYS MCQ solution video, plus full Sec 3 / Sec 4 topic recordings.

Find out more