
Answer: D (curve 2 steeper, both reaching the same final volume). The reaction is \(\text{Mg} + 2\text{HCl} \to \text{MgCl}_2 + \text{H}_2\). With 1.2 g of magnesium, \(n(\text{Mg}) = 1.2/24 = 0.050\) mol, needing 0.10 mol of HCl to react completely.
Experiment 1: \(0.100 \times 1 = 0.100\) mol HCl. Experiment 2: \(0.050 \times 2 = 0.100\) mol HCl. Both supply exactly 0.10 mol of acid, so both fully react the same 0.050 mol of magnesium and produce the same 0.050 mol of hydrogen. Both curves therefore plateau at the same final volume.
Experiment 2 uses the more concentrated acid (2 mol/dm³), so collisions are more frequent and the reaction is faster: curve 2 rises more steeply at the start before levelling off at the same height. That is graph D. The common error is to expect different final volumes, but the moles of hydrogen are identical.
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