
Answer: B (\(\text{Y}^{2+}\) and \(\text{Z}^{-}\), formula \(\text{YZ}_2\)). The ratio of positive to negative ions is found by inverting the coordination numbers. Each positive ion is surrounded by 8 negative ions and each negative ion by 4 positive ions, so positive : negative = 4 : 8 = 1 : 2.
The formula unit therefore has one positive ion to two negative ions: \(\text{YZ}_2\). For the compound to be neutral, \((\text{charge on Y}) + 2 \times (\text{charge on Z}) = 0\), so Y must be \(2+\) and Z must be \(1-\).
Only option B gives \(\text{Y}^{2+}\), \(\text{Z}^{-}\) and \(\text{YZ}_2\). Answer B.
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