Answer: B (\(\text{C}_2\text{H}_5\text{CO}_2\text{H}\)). The complete oxidation of a primary alcohol gives the carboxylic acid with the same number of carbon atoms.
Propan-1-ol, \(\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}\) (3 carbons), is oxidised to propanoic acid, \(\text{CH}_3\text{CH}_2\text{CO}_2\text{H}\), which is written \(\text{C}_2\text{H}_5\text{CO}_2\text{H}\) (also 3 carbons).
A is ethanoic acid (2 carbons), C is butanoic acid (4 carbons) and D has 5 carbons. The carbon count must be preserved, so only B fits. Answer B.
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