Answer: D (\(\text{Mg(s)} \rightarrow \text{Mg}^{2+}\text{(aq)} + 2\text{e}^{-}\)). In sacrificial protection a more reactive metal is attached to the iron. Magnesium loses electrons more readily than iron, so it is preferentially oxidised and corrodes instead of the steel.
The protective process is the oxidation of magnesium: \(\text{Mg} \rightarrow \text{Mg}^{2+} + 2\text{e}^{-}\).
A and B show iron corroding, the very thing the magnesium prevents. C shows \(\text{Mg}^{2+}\) being reduced to magnesium, the reverse of what happens. Answer D.
Every O Level Pure Chemistry TYS MCQ solution video, plus full Sec 3 / Sec 4 topic recordings.
Find out more