
Answer: B. Cracking decane, \(\text{C}_{10}\text{H}_{22}\), into ethane (\(\text{C}_2\text{H}_6\)), ethene (\(\text{C}_2\text{H}_4\)) and propene (\(\text{C}_3\text{H}_6\)) must balance all atoms.
One ethane, one ethene and two propene give carbon \(2 + 2 + 6 = 10\) and hydrogen \(6 + 4 + 12 = 22\), matching \(\text{C}_{10}\text{H}_{22}\). The ratio is 1 : 1 : 2.
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