Answer: C. At the negative electrode, lead(II) ions gain electrons and are reduced to lead: \(\text{Pb}^{2+} + 2\text{e}^{-} \rightarrow \text{Pb}\).
A is wrong (chloride ions lose, not gain, electrons) and D is wrong (lead ions move to the negative electrode and gain electrons, they do not lose them at the positive electrode).
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