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2017 O Level Chem P1 Q11 — Electrolysis / Quantitative Electrolysis Solution

Electrolysis / Quantitative Electrolysis 2017 O Level Pure Chemistry · Paper 1 · Q11

Question

In an electrolysis experiment, the same amount of charge deposited 6 g of titanium and 16 g of copper. The charge on the copper ion was 2+. [Ar: Ti, 48; Cu, 64] What was the charge on the titanium ion?

A1+
B2+
C3+
D4+

Correct answer: D

Video Solution

Explanation

Answer: D. The same charge passes through both. For copper, \(16 \div 64 = 0.25\) mol of \(\text{Cu}^{2+}\), needing \(0.25 \times 2 = 0.50\) mol of electrons.

That same 0.50 mol of electrons deposited \(6 \div 48 = 0.125\) mol of titanium. The charge per titanium ion is \(0.50 \div 0.125 = 4\), so the ion is \(\text{Ti}^{4+}\).

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