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2025 H2 Chem P1 Q8 — Thermodynamics Solution

Thermodynamics 2025 A-Level H2 Chemistry · Paper 1 · Q8

Question

A hydrogen–oxygen fuel cell releases energy by oxidising hydrogen at one electrode and reducing oxygen at the other electrode. The ions produced then combine to form water.

The overall process is summarised by the following equation.

\(2\text{H}_2\text{(g)} + \text{O}_2\text{(g)} \rightarrow 2\text{H}_2\text{O(l)}\)

Which row correctly shows the signs for \(\Delta H\), \(\Delta S\) and \(\Delta G\) for this process in the hydrogen–oxygen fuel cell at room temperature?Question diagram
  1. AA
  2. BB
  3. CC
  4. DD
Correct answer: A

Video Solution

Explanation

The answer is A (\(\Delta H\) negative, \(\Delta S\) negative, \(\Delta G\) negative).
• \(\Delta H\): forming water from hydrogen and oxygen (the same overall reaction as burning hydrogen) is strongly exothermic, so \(\Delta H\) is negative.
• \(\Delta S\): 3 mol of gas (2 mol \(\text{H}_2\) + 1 mol \(\text{O}_2\)) become 2 mol of liquid water. The number of ways of arranging the particles and their energy decreases, so \(\Delta S\) is negative.
• \(\Delta G\): the reaction in the fuel cell takes place spontaneously and does useful electrical work, so \(\Delta G\) is negative. At room temperature the large negative \(\Delta H\) outweighs the \(-T\Delta S\) term, which is positive.
• B is wrong: \(\Delta G\) is not positive, because the cell reaction is spontaneous.
• C is wrong: \(\Delta H\) is not positive, because forming water from hydrogen and oxygen is exothermic.
• D is wrong: \(\Delta S\) is not positive, because gases are converted into a smaller amount of liquid.

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