The answer is A.
Ethanoyl chloride reacts with aminoethane in a condensation reaction to give the amide N-ethylethanamide:
\(\text{CH}_3\text{COCl} + \text{C}_2\text{H}_5\text{NH}_2 \rightarrow \text{C}_2\text{H}_5\text{NHCOCH}_3 + \text{HCl}\)
• B is wrong: with phenol the product is the ester phenyl ethanoate, \(\text{CH}_3\text{CO}_2\text{C}_6\text{H}_5\). The formula \(\text{CH}_3\text{COC}_6\text{H}_5\) is missing the ester oxygen (it is a ketone).
• C is wrong: with propan-2-ol the product is \(\text{CH}_3\text{CO}_2\text{CH(CH}_3)_2\). The formula given has a \(\text{C}_2\text{H}_5\) group on the carbonyl carbon, one carbon too many for an ethanoyl group.
• D is wrong: water hydrolyses ethanoyl chloride to the carboxylic acid, \(\text{CH}_3\text{COCl} + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{CO}_2\text{H} + \text{HCl}\), not to the aldehyde \(\text{CH}_3\text{CHO}\).
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