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2025 H2 Chem P1 Q21 — Carboxylic Acid Solution

Carboxylic Acid 2025 A-Level H2 Chemistry · Paper 1 · Q21

Question

An ester, J, is hydrolysed by heating with aqueous sulfuric acid. The resulting reaction mixture is heated under reflux with acidified potassium dichromate (VI) solution. The final mixture of products contains only one organic compound.

what could ester J be?

1) \(\text{CH}_3\text{CO}_2\text{C}_2\text{H}_5\)
2) \(\text{CH}_3\text{CH}_2\text{CO}_2\text{CH(CH}_3)_2\)
3) \(\text{CH}_3\text{CH}_2\text{CH}_2\text{CO}_2\text{CH}_2\text{CH}_3\)
  1. A1 and 2
  2. B1 only
  3. C2 and 3
  4. D3 only
Correct answer: B

Video Solution

Explanation

The answer is B (1 only).
Acid hydrolysis splits each ester into a carboxylic acid and an alcohol. Heating under reflux with acidified \(\text{K}_2\text{Cr}_2\text{O}_7\) then oxidises the alcohol (a primary alcohol to a carboxylic acid, a secondary alcohol to a ketone). Only one organic compound remains if the oxidised alcohol gives the same compound as the acid.
• 1: \(\text{CH}_3\text{CO}_2\text{C}_2\text{H}_5\) gives \(\text{CH}_3\text{CO}_2\text{H}\) and \(\text{C}_2\text{H}_5\text{OH}\); ethanol is oxidised to \(\text{CH}_3\text{CO}_2\text{H}\). The only product is ethanoic acid, so 1 is correct.
• 2: \(\text{CH}_3\text{CH}_2\text{CO}_2\text{CH(CH}_3)_2\) gives \(\text{CH}_3\text{CH}_2\text{CO}_2\text{H}\) and propan-2-ol; propan-2-ol is oxidised to propanone, \(\text{CH}_3\text{COCH}_3\). Two products (propanoic acid and propanone), so 2 is wrong.
• 3: \(\text{CH}_3\text{CH}_2\text{CH}_2\text{CO}_2\text{CH}_2\text{CH}_3\) gives \(\text{CH}_3\text{CH}_2\text{CH}_2\text{CO}_2\text{H}\) and ethanol; ethanol is oxidised to \(\text{CH}_3\text{CO}_2\text{H}\). Two products (butanoic acid and ethanoic acid), so 3 is wrong.
• A, C and D are wrong because they include 2 or 3, or leave out 1.

Worked solution diagram

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