
The answer is D (3 only).
Cold NaOH(aq) reacts only with the groups in X that are acidic enough to be neutralised; it does not hydrolyse the amide group at room temperature.
• Group 1 does not react: an alcohol is a weaker acid than water, so the alcoholic OH group does not react with NaOH(aq).
• Group 2 does not react: an amide is neutral, and its hydrolysis by NaOH(aq) needs prolonged heating, not cold conditions.
• Group 3 reacts: phenol is weakly acidic because the negative charge of the phenoxide ion is delocalised into the benzene ring. It is neutralised by cold NaOH(aq): \(\text{ArOH} + \text{NaOH} \rightarrow \text{ArO}^-\text{Na}^+ + \text{H}_2\text{O}\).
• A is wrong: it includes group 1, the alcoholic OH, which does not react.
• B is wrong: it includes group 2, the amide, which is not hydrolysed without heating.
• C is wrong: the amide does not react, and the phenolic OH group, which does react, is left out.
Join a live JC H2 Chemistry class at Bukit Timah, Tampines, or online. Come for a trial lesson, no obligation.
Book a trial class20+ more Nitrogen Compound questions with shuffled options in ChemBank, free for everyone. Want more? The ChemBank Premium ($100/month) unlocks 4,000+ TYS and Prelim questions, Paper 2 & 3 practice with worked solutions, and all simulations.
Open ChemBank free