Born Haber Cycle
Born Haber Cycle Born Haber Cycle Diagram Using the acronym F.A.I.L. where F stands for enthalpy change of formation of the ionic compound, A stands for atomisation of the constituent elements and I stands for ionisation of cation and anion and L stands for Lattice Energy. We have four major components  and this energy cycle is easy to draw with no worries about which species having a higher energy level. There is no need to include electrons as they are immediately used to form the anion. Hope this has been useful to you! Share it with your friends if it has helped you 🙂 Back to Home of Leading H2 Chemistry Tuition Centre ...
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Hydrolysis of Esters and Amides
Hydrolysis of Esters and Amides I've specially highlighted how the water molecule breaks up and adds to the hydrolysis products. Let me know if there's anything that you would like me to clarify. Here's links to other organic tips. Back to Home of Singapore's Leading JC H2 Chemistry Tuition ...
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JC Chemistry Tuition in Bishan
JC Chemistry Tuition in Bishan We will be starting classes at Bishan this June, on Monday and Friday evenings. For a start, there will be two JC2 classes and one JC1 class. Went down to the area to take a professional photoshoot and it was quite good.  The location of the unit is very convenient, walking distance from the interchange. Do check out our class schedule if you are interested to sign up for H2 Chemistry Tuition. Back to Home of Top A levels Chemistry Tutor ...
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Organic Novel Questions Book
Organic Novel Questions Book By the time this post is published, hopefully we would have finished the proofreading and sent for printing. Distribution to the bookstores might take a month or so but i hope to make it in time for the 2019 A levels Examination. This is my second book and i hope it will cater to a different group of students. If you recall, my first book was to meet the demand from private candidates who needed practical worksheets for practice. This Organic Novel Questions Book hopes to address the needs of students who are competent doing the standard questions and want to stretch themselves.  This doesn't mean that average students shouldn't buy the book. It only means ...
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FRS Chemical Environment
FRS Chemical Environment FRS Chemical Environment U and V are structural isomers with molecular formula C7H16. Both U and V produce the same number of possible structural isomers upon reaction with chlorine to form monochlorinated compounds with the formula C7H15Cl. Which pairs are possible structures of U and V? Have a look at the different colour coded hydrogen atoms. Those with the same colour is the same type of hydrogen, i.e. they will form the same product if they are substituted by chlorine.  Do look out for plane of symmetry as it will greatly accelerate the speed at which you identify FRS Chemical environment. So answer is 1 and 3 only! If you've enjoyed this organic MCQ, do share it ...
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Free Radical Substitution MCQ Analysis
Free Radical Substitution MCQ This MCQ is about free radical substitution, be sure to read up before looking at the solution! Which of the following is a possible product in the reaction between cyclohexane and bromine with UV light? Analysis:  The common answer dicyclohexane isn't one of the given options. So we will have to choose from the above options. Solution: A: Note that this option has a total of 14 carbon atoms, not 18. The cyclohexane radicals all has 6 carbon atoms so the products should be in multiples of 6. B: Similarly, this option has a total of 13 carbon atoms, not 18. C: This option has 16 carbon atoms. D: This option has 18 carbon atoms and ...
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Organic Chemistry MCQ Analysis
Organic Chemistry MCQ Organic Chemistry MCQ: Which of the following compounds exhibit cis–trans isomerism? Analysis: The question is straightforward. Which compounds exhibit cis-trans isomerism? In the Chemistry H2 syllabus, we learnt about the two criteria for cis-trans isomerism. Presence of C=C bond Different atoms/group of atoms bonded to each of the carbon atoms Although in the H2 Chemistry syllabus, it is required that C=C bond cannot be in a cyclic structure. Looking at the three options, looks like none of them can exhibit cis-trans isomerism! But this cannot be the case, let us examine the options carefully. The three options examined Option 1: Although there's no C=C, there is a four-carbon ring structure which restricts rotation. Moreover, the two central ...
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Solving Organic Deductive Questions
Solving Organic Deductive Questions Compound J, C8H6O4, forms a molecule K, C8H10O3, when reacted with LiAlH4 in dry ether. However, when J was reacted with NaBH4 instead, a product of molecular formula C8H8O4 was formed. J gives an orange precipitate with 2,4-dinitrophenylhydrazine but does not give any precipitate when warmed with Fehling’s reagent. K reacts with bromine water to form L, C8H7O3Br3. Suggest the structures of J, K and L.              Solution: First information is the molecular formula, it has almost the same C to H ratio and has more than six carbons => likely to have benzene ring C6H6 (Note that there is still two carbon atoms not accounted for) When it undergoes reduction with LiAlH4, 4 hydrogen atoms were ...
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